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Time & Work questions become simple once you stop thinking in days and start thinking in "work done per day" — the efficiency method.
If a person can finish a job in n days, their one-day work (efficiency) is 1/n of the job. Add efficiencies to combine workers; total time = 1 ÷ (combined efficiency).
Same idea — an inlet pipe adds to the work (fills the tank), an outlet pipe subtracts from it (empties the tank).
An UdaanPath content writer, A, can draft one full mock-test paper (100 questions) in 10 days. Another writer, B, takes 15 days for the same paper. If they split the work and draft it together, how long will it take?
A's efficiency = 1/10, B's efficiency = 1/15. Combined = 1/10 + 1/15 = 3/30 + 2/30 = 5/30 = 1/6. Together they take 6 days.
Writer A can draft a paper alone in 12 days. Working together, A and B finish it in 8 days. How long would B alone take?
B's efficiency = 1/8 − 1/12 = 3/24 − 2/24 = 1/24. B alone takes 24 days.
Pipe A fills a tank in 6 hours, pipe B empties it in 9 hours. If both are opened together, how long to fill the tank?
Net efficiency = 1/6 − 1/9 = 3/18 − 2/18 = 1/18. Tank fills in 18 hours.
Don't average the number of days directly (e.g. assuming two workers taking 10 and 15 days together take 12.5 days) — always work through efficiencies (1/n), never raw day-counts.
1. A can finish a task in 8 days, B in 12 days. Working together, how many days will they take?
2. An UdaanPath writer can draft a mock paper in 15 days. Working with a colleague, they finish it in 10 days. How long would the colleague alone take?
3. A pipe fills a tank in 4 hours; a second pipe empties it in 8 hours. If both are open together, how long to fill the tank?